Answer:
Here. \[{{\text{E}}_{\text{1}}}={{\text{E}}_{\text{2}}}\]
\[\frac{1}{2}{{m}_{1}}\upsilon
_{1}^{2}=\frac{1}{2}{{m}_{2}}\upsilon _{2}^{2}\] or \[\frac{\upsilon
_{2}^{2}}{\upsilon _{1}^{2}}=\frac{{{m}_{1}}}{{{m}_{2}}}\] or \[\frac{{{\upsilon
}_{2}}}{{{\upsilon }_{1}}}=\sqrt{\frac{{{m}_{1}}}{{{m}_{2}}}}\]
As \[{{\text{p}}_{\text{2}}}=\text{
}{{\text{m}}_{\text{2}}}{{\upsilon }_{\text{2}}}\]and \[{{\text{p}}_{\text{1}}}=\text{
}{{\text{m}}_{\text{1}}}{{\upsilon }_{\text{1}}}\]
\[\frac{{{p}_{2}}}{{{p}_{1}}}=\frac{{{m}_{2}}{{\upsilon
}_{2}}}{{{m}_{1}}{{\upsilon }_{1}}}=\frac{{{m}_{2}}}{{{m}_{1}}}.\sqrt{\frac{{{m}_{1}}}{{{m}_{2}}}}=\sqrt{\frac{m_{2}^{2}{{m}_{1}}}{m_{1}^{2}{{m}_{2}}}}\]
\[\frac{{{p}_{2}}}{{{p}_{1}}}=\sqrt{\frac{{{m}_{2}}}{{{m}_{1}}}}\];
If \[{{\text{m}}_{\text{2}}}>{{\text{m}}_{\text{1}}}\], then \[{{\text{p}}_{\text{2}}}>{{\text{p}}_{\text{1}}}\]
i.e. a heavier body has greater linear momentum.
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