Answer:
Here, \[U\,=-A/{{x}^{6}}\],
F = ?
From \[{{F}_{x}}=-\frac{d}{dx}\left(
U \right)=-\frac{d}{dx}\left( \frac{-A}{{{x}^{6}}} \right)=A\left(
\frac{-6}{{{x}^{7}}} \right)\]
\[\therefore \] force
exerted by one atom on another atom = \[-6\,A/{{x}^{7}}\]
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