11th Class Physics Physical World / भौतिक जगत Question Bank 11th CBSE Physics Mathematical Tools, Units & Dimensions

  • question_answer
    Four physical quantities are listed in column I. Their values are listed in column II in random order. Match the columns correctly. Column I Column II 1.Thermal energy of air molecule at room temperature 2. Binding energy of heavy nuclei per nucleon 3. X-ray photon energy 4. Photon energy of visible light 0.02 eV 2 eV 1 keV 7 MeV

    Answer:

                    1. Thermal energy of air molecule at room temp. = \[\frac{3}{2}kT=\frac{3}{2}\times 1.38\times {{10}^{-23}}\times 300=621\times {{10}^{-21}}J=\frac{6.21\times {{10}^{-21}}}{1.6\times {{10}^{-19}}}=0.039eV\]                                                                                                       \[\therefore\] Thermal energy of air molecule at room temp.                                                                                           \[\approx 0.0\text{2 eV}\] . 2. Binding energy of heavy nuclei per nucleon is of the order of 7 MeV. 3. As X-rays are produced by potential diff. of the order of kilovolts across the X-ray tube, therefore, X-ray photon energy is of the order of 1 keV. 4. Photon energy of visible light comes from de-excitation of atoms-which are ionised by a few eV. Therefore, this energy is of the order of 2 eV.


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