Answer:
\[\text{d}=\frac{\text{MP}}{\text{RT}}\]
(Refer to page 5/22) or\[P=\frac{\text{dRT}}{\text{M}}\].
Hence, \[\frac{{{P}_{2}}}{{{P}_{1}}}=\frac{{{d}_{2}}{{T}_{2}}}{{{d}_{1}}{{T}_{1}}}\,\]
or \[{{P}_{2}}=\frac{{{P}_{1}}{{T}_{2}}}{{{T}_{1}}}\,\left(
\frac{{{d}_{2}}}{{{d}_{1}}} \right)\] \[=\frac{760\times 263}{273}\,\left(
\frac{1}{10} \right)=73\cdot 2\,\text{mm}\text{.}\]
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