Answer:
(i) The roots for 1 and 9 are un and enn respectively. Therefore, the name for the element with Z = 119 is un + un + enn + ium = ununennium and its symbol is Uue.
(ii) The maximum number of elements which can be accommodated in the present set up of the long form of the periodic table = 118 (For details refer to Q. 2, page 3/91). Since this last element would be an inert gas, therefore, the element with Z = 119 will be an alkali metal and hence its outer electronic configuration will be \[8{{s}^{1}}\] or its complete electronic configuration will be\[1{{s}^{2}}2{{s}^{2}}2{{p}^{6}}3{{s}^{2}}3{{p}^{6}}3{{d}^{10}}\]\[4{{s}^{2}}4{{p}^{6}}4{{d}^{10}}4{{f}^{14}}5{{s}^{2}}\] \[5{{p}^{6}}5{{d}^{10}}5{{f}^{14}}6{{s}^{2}}\,6{{p}^{6}}\,6{{d}^{10}}\]\[7{{s}^{2}}7{{p}^{6}}\,8{{s}^{1}}\].
(iii) Since the element with Z = 119 will be an alkali metal, therefore, formula of its chloride will be MCl and that of its stable oxide will be bold \[{{M}_{2}}O\] where M is the alkali metal.
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