Answer:
(i) The empirical formula for the
compound containing A and D is \[A{{D}_{2}}\]. This is because atom A has two
valence electrons while D has seven electrons. Therefore, A donates two
electrons to two atoms of D and the compound has the formula \[A{{D}_{2}}\].
(ii) The empirical formula for the
compound is BD because B loses one electron while D accept it.
(iii) Two atoms of D can share
one electron each to complete their octet. Therefore, the empirical formula of
the compound is \[{{D}_{2}}\].
(iv) Since E has the
configuration of a noble gas (Ne), it is, therefore, mono atomic and exists as
E.
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