Answer:
(a) Bond energy of \[N_{2}^{+}=\]
Bond energy of \[N_{2}^{-}\]. This is because they have the same bond order.
(Strictly speaking, \[N_{2}^{-}\] is
slightly less stable and hence has less bond energy than \[N_{2}^{+}\] due to
presence of greater number of electrons in the anti bonding molecular orbitals)
(b) (i) Same bond order and bond
length, (ii) Same bond order and bond length.
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