Answer:
Due to H-bonding in HF, we have\[H-F\text{------}H-F\text{------}H-F\text{------}\]
This can dissociate to give \[HF_{2}^{-}\]
ion and hence \[KH{{F}_{2}}\]exists but there is no H-bonding in \[H-Cl\]. So \[HCl_{2}^{-}\]
ion does not exist and hence \[KHC{{l}_{2}}\] also does not exist.
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