11th Class Chemistry Chemical Bonding and Molecular Structure Question Bank 11th CBSE Chemistry Chemical Bonding and Molecular Structure

  • question_answer (a) How bond energy varies from \[N_{2}^{-}\] to \[N_{2}^{+}\] and why? (b) On the basis of molecular orbital theory what is similarity between (i) \[{{F}_{2}},\,O_{2}^{--}\]        (ii) \[CO,\,{{N}_{2}},\,N{{O}^{+}}\]?

    Answer:

                    (a) Bond energy of \[N_{2}^{+}=\] Bond energy of \[N_{2}^{-}\]. This is because they have the same bond order. (Strictly speaking, \[N_{2}^{-}\] is slightly less stable and hence has less bond energy than \[N_{2}^{+}\] due to presence of greater number of electrons in the anti bonding molecular orbitals) (b) (i) Same bond order and bond length, (ii) Same bond order and bond length.


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