Answer:
\[C-H({{C}_{2}}{{H}_{6}})>C-H({{C}_{2}}{{H}_{4}})>C-H({{C}_{2}}{{H}_{2}}).\]
This is because hybrid orbitals of carbon involved in overlapping
with 1 s orbital of hydrogen are \[s{{p}^{3}},\,s{{p}^{2}}\]
and sp respectively and their sizes are in the order \[s{{p}^{3}}>s{{p}^{2}}>sp\]
.
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