Answer:
The size of \[N{{a}^{+}}\] ion is
bigger as compared to that \[L{{i}^{+}}\] ion and, therefore, the magnitude
positive charge around it is comparatively less. It is not in a position to
provide stability to oxide ion \[({{O}^{2-}})\] with high electron density.
However, it can hold relatively large peroxide ion\[{{(O-O)}^{2-}}\] more
easily since the negative charge on it is quite dispersed. \[L{{i}^{+}}\]ion,
on the other hand, can accommodate oxide ion as it has a greater positive
charge density around it.
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