Series | Parallel | |
Circuit 1 | ||
Circuit 2 |
Answer:
(b) (i) If one electrical heater stops working due to some
defect then other keeps working normally.
(ii) Each
electrical appliance (heater) gets the same voltage (220 V) as that of the
power supply line.
(c)
Effective resistance, R=4+6=10
Current, =1.2A
Voltmeter
reading = 12 V
(d)
Combined resistance,
(e) Current
=5A
2=2A
(i)
The current in resistor
= 5A - 2A
=3A
(ii)
The power supplied to resistor =
=12x2
=24W
(iii) The energy transformed in resistor in 300 s = E = P x t
=24 x 300
s= 7200 J
Series
Parallel
Circuit 1
Circuit 2
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