Series | Parallel | |
Circuit 1 | ||
Circuit 2 |
Answer:
(b) (i) If one electrical heater stops working due to some
defect then other keeps working normally.
(ii) Each
electrical appliance (heater) gets the same voltage (220 V) as that of the
power supply line.
(c)
Effective resistance, R=4+6=10
Series
Parallel
Circuit 1
Circuit 2
Current
, =1.2A
Voltmeter
reading = 12 V
(d)
Combined resistance,
(e) Current
=5A
2=2A
(i)
The current in resistor
= 5A - 2A
=3A
(ii)
The power supplied to resistor
=
=12x2
=24W
(iii) The energy transformed in resistor
in 300 s = E = P x t
=24 x 300
s= 7200 J
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