6th Class Mathematics Whole Numbers

  • question_answer 10)
    Find the product by suitable rearrangement. (a) 2 x 1768 x 50                (b) 4 x 166 x 25                  (c) 8 x 291 x 125                 (d) 625 x 279 x 16 (e) 285 x 5 x 60                  (f) 125 x 40 x 8 x 25 TIPS First, we multiply those two numbers, which can give us zero (0) like 100, 1000 etc. Because, to multiply any number with these numbers is   simple.                                                     

    Answer:

                    (a) We have,      2 x 1768 x 50 = (2 x 50) x 1768 = 100 x 1768 = 176800 (b) We have,      4 x 166 x 25 = (4 x 25) x 166 = 100 x 166 =16600 (c) We, have,     8 x 291 x 125 = (8 x 125) x 291 =1000 x 291 = 291000 (d) We have,      625 x 279 x 16 = (625 x 16) x 279 = 10000 x 279 = 2790000 (e) We have,      285 x 5 x 60 = (5 x 60) x 285 = 300 x 285 = 85500 (f) We have,       125 x 40 x 8 x 25 = (125 x 40) x (8 x 25) = 5000 x 200 = 1000000


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