Answer:
(i) Here, we draw a \[\Delta ABC.\] In which, AB = 3 cm, BC = 3.5 cm and AC = 39 cm Now, by adding two sides of \[\Delta ABC\] i.e. AB + BC = 3 + 3.5 = cm Clearly, AB + B C > AC (ii) Here, we draw a \[\Delta ABC\]in which AB = 3 cm, BC = 4 cm and AC = 5 cm Now, by adding two sides of \[\Delta ABC\] i.e. AB + BC = 3 + 4 = 7 cm Clearly, AB + BC > AC (iii) Here, we draw a \[\Delta ABC\]in which AB = BC = AC = 2.5 cm Now, by adding two sides of \[\Delta ABC\] i.e. AB + BC = 2.5 + 2.5 = 5 cm Clearly, AB + BC > AC (iv) Here, we draw a \[\Delta ABC\] in which AB = 3 cm, BC = 3.5 cm and AC =4 cm Now, by adding two sides of \[\Delta ABC\] i.e. AB + BC = 3 + 3.5 = 6.5 cm Clearly, AB + BC > AC (v) Here, we draw a \[\Delta ABC\] in which AB = 2 cm, BC = 4 cm and AC = 45 cm Now, by adding two sides of \[\Delta ABC\] i.e. AB + BC = 2 + 4 = 6 cm Clearly, AB + BC > AC From all these conclusions, we observe that in each case, the sum of the lengths of any two sides is greater than the third 4 cm side. So, the sum of the lengths of any two sides can never be less than the third side.
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