question_answer 13)

Find the product: (i) \[\frac{9}{2}\times \left( \frac{-7}{4} \right)\]                                (ii) \[\frac{3}{10}\times -9\]                         (iii) \[\frac{-6}{5}\times \frac{9}{11}\]                            (iv) \[\frac{3}{7}\times \left( \frac{-2}{5} \right)\] (v) \[\frac{3}{11}\times \frac{2}{5}\]                       (vi) \[\frac{3}{-5}\times \frac{-5}{3}\]

Answer:

                (i) \[\frac{9}{2}\times \left( \frac{-7}{4} \right)=\frac{9\times -7}{2\times 4}=\frac{-63}{8}=-7\frac{2}{8}\] (ii) \[\frac{3}{10}\times (-9)=\frac{3\times (-9)}{10}=\frac{-27}{10}=-2\frac{7}{10}\] (iii) \[\frac{-6}{5}\times \frac{9}{11}=\frac{-6\times 9}{5\times 11}=\frac{-54}{55}\] (iv) \[\frac{3}{7}\times \left( \frac{-2}{5} \right)=\frac{3\times (-2)}{7\times 5}=\frac{-6}{35}\] (v) \[\frac{3}{11}\times \frac{2}{5}=\frac{3\times 2}{11\times 5}=\frac{6}{55}\] (vi) \[\frac{3\times (-5)}{-5\times 3}=\frac{-15}{-15}=1\]