Answer:
So, to find the line of symmetry of angle \[{{75}^{o}}\], we use the following steps: Step I Draw \[{{l}_{1}},{{l}_{2}},{{l}_{3}}\] of any length. Step II Place the centre of the protractor at A and the zero edge along \[{{l}_{4}}\] Step III Start with zero near B, mark point C at \[{{75}^{o}}\]. Step IV Join \[{{l}_{1}},{{l}_{2}},{{l}_{3}}\]is the required angle of measure \[{{75}^{o}}\]. Step V With A as centre and using compasses, draw an arc that cuts both rays of \[{{l}_{4}}\] at P and Q. Step VI With P as centre, draw (in the interior of \[{{l}_{1}}\] an arc whose radius is more than half of the length of PQ). Step VII With the same radius and with Q as centre, draw another arc in the interior of \[{{l}_{1}},{{l}_{2}},{{l}_{3}},{{l}_{4}},{{l}_{5}}\]. Let the two arcs intersect at D. Step VIII Join AD, then \[\overline{AD}\] is the required bisector of \[\angle A\]. i.e. AD is the line of symmetry of an angle of measure \[{{75}^{o}}\].
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