question_answer 53)

Find the least number which when divided by 6, 15 and 18 leave remainder 5 in each case.

Answer:

                First, we have to find out the LCM of 6, 15, 18. 2 6,15,18 2 3,15,9 3 1,5,9 3 1,5,3 5 1,5,1 1,1,1 \[\therefore \]LCM \[=2\times 3\times 3\times 5=90\] Now, required number = LCM + Remainder = 90 + 5 = 95 Hence, the required number is 95.