3 | A | |
+ | 2 | 5 |
B | 2 |
4 | A | |
+ | 9 | 8 |
C | B | 3 |
1 | A | |
\[\times \] | A | |
9 | A |
A | B | |
+ | 3 | 7 |
6 | A |
A | B | |
\[\times \] | 3 | |
C | A | B |
A | B | |
\[\times \] | 5 | |
C | A | B |
A | B | |
\[\times \] | 6 | |
B | B | B |
A | 1 | |
+ | 1 | B |
B | 0 |
2 | A | B |
+ A | B | 1 |
B | 1 | 8 |
1 | 2 | A |
+ 6 | A | B |
A | 0 | 9 |
Answer:
1. Here, there are two letters A and B whose values are to be found out. Let us see the sum in unit's column. It is \[A+5\]and we get 2 from this. So A has to be 7 \[(\because \,\,A+5=7+5=12)\] Now, for sum in ten's column, we have \[1+3+2=B\] \[\Rightarrow \] \[B=6\] Therefore, the puzzle is solved as shown below:
3 | 7 | |
+ | 2 | 5 |
6 | 2 |
4 | 5 | |
+ | 9 | 8 |
1 | 4 | 3 |
1 | 1 | |
\[\times \] | 1 | |
1 | 1 |
1 | 5 | |
\[\times \] | 5 | |
7 | 5 |
1 | 6 | |
\[\times \] | 6 | |
9 | 6 |
2 | 5 | |
+ | 3 | 7 |
6 | 2 |
A | 0 | |
\[\times \] | 3 | |
C | A | 0 |
5 | 0 | |
\[\times \] | 3 | |
1 | 5 | 0 |
A | 0 | |
\[\times \] | 5 | |
C | A | 0 |
5 | 0 | |
\[\times \] | 5 | |
2 | 5 | 0 |
A | 5 | |
\[\times \] | 5 | |
C | A | 5 |
2 | 5 | |
\[\times \] | 5 | |
1 | 2 | 5 |
A | B | |
\[\times \] | 6 | |
B | B | B |
7 | 4 | |
\[\times \] | 6 | |
4 | 4 | 4 |
A | 1 | |
+ | 1 | 9 |
9 | 0 |
2 | A | 7 |
+ A | 7 | 1 |
7 | 1 | 8 |
2 | 4 | 7 |
+ 4 | 7 | 1 |
7 | 1 | 8 |
1 | 2 | 8 |
+ 6 | 8 | B |
8 | 0 | 9 |
1 | 2 | 8 |
+ 6 | 8 | 1 |
8 | 0 | 9 |
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