Answer:
For getting the maximum value of weight, we have to find out the HCF of 75 kg and 69 kg. i.e. 3 75 3 69 5 25 23 23 5 5 1 1
\[\therefore \] Prime factorisation of \[75=\times 5\times 5\] Prime factorisation of \[69=\times 23\] Common factor of 75 and 69 is 3. Thus, HCF of 75 kg and 69 kg = 3 kg Hence, required maximum value of weight is 3 kg.
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