Answer:
Length of the wire \[=\text{44 cm}\] Let the radius of the circle be r cm. Then, circumference of the circle \[\text{= 2 }\!\!\pi\!\!\text{ r cm}\] According to the question, \[2\pi r=44\] \[\Rightarrow \] \[2\times \frac{22}{7}\times r=44\] \[\Rightarrow \] \[\text{r =}\frac{\text{44 }\!\!\times\!\!\text{ 7}}{\text{2 }\!\!\times\!\!\text{ 22}}\text{= 7cm}\] Hence, the radius of that circle is 7 cm. Area of the circle \[=\pi {{r}^{2}}\] \[\text{= }\frac{\text{22}}{\text{7}}{{\text{(7)}}^{\text{2}}}\text{ c}{{\text{m}}^{\text{2}}}\text{ = 154 c}{{\text{m}}^{\text{2}}}\] Length of each side of the square \[\text{= }\frac{\text{Perimeter of the square}}{\text{4}}\] \[\text{= }\frac{\text{Length of the wire}}{\text{4}}\text{ = }\frac{\text{44}}{\text{4}}\text{cm = 11cm}\] \[\therefore \] Area of the square \[=\text{side}\times \text{side}\] \[\text{= 11 }\!\!\times\!\!\text{ 11 c}{{\text{m}}^{\text{2}}}\text{= 121 c}{{\text{m}}^{\text{2}}}\] Hence, the circle encloses more area.
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