Answer:
Let the number be \[x\]. Then, according to the question, \[\left( x-\frac{5}{2} \right)\,8=3x\] \[\Rightarrow \] \[8x-\frac{5}{2}\times 8=3x\] \[\Rightarrow \] \[8x-20=3x\] \[\Rightarrow \] \[8x-3x=20\] |Transposing \[3x\] to LHS and ? 20 to RHS \[\Rightarrow \] \[5x=20\] \[\Rightarrow \] \[x=\frac{20}{5}=4\] | Dividing both sides by 5 Hence, the required number is 4. Check: \[\left( 4-\frac{5}{2} \right)8=\frac{8-5}{2}\times 8\] \[=\frac{3}{2}\times 8=3\times 4=12\] \[3x=3\times 4=12\] Hence, the result is verified.
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