question_answer 1)

Make five more such pairs and put appropriate signs.

Answer:

Five more such pairs may be taken us under (i) \[\therefore \] (ii) \[\frac{1}{18}+\frac{1}{18}\] (iii) \[\frac{8}{15}+\frac{3}{15}\] (iv) \[\frac{7}{7}+\frac{5}{7}\] (v) \[\frac{1}{22}+\frac{21}{22}\] After putting the appropriate signs, we have (i)\[\frac{12}{15}-\frac{7}{15}\] (ii)\[\frac{5}{8}+\frac{3}{8}\] (iii)\[1-\frac{2}{3}\] (iv)\[\frac{1}{4}+\frac{0}{4}\] (v)\[3-\frac{12}{5}\]