7th Class Mathematics Decimals and Fractions

  • question_answer 35)
    Dinesh went from place A to place B and from there to place C. A is 7.5km from B and B is 12.7 km from C. Ayub went from place A to place D and from there to place C. D is 9.3 km from A and C is 11.8 km from D. Who travelled more and by how much?

    Answer:

                    For Dinesh Distance between place A and place B = 7.5 km Distance between place B and place C = 12.7 km \[\therefore \]  Distance between place A and place C = Distance between place A and place B + Distance between place B and place C = 7.5 km + 12.7km                                       \[\text{=20}\text{.2 km}\]                           \[\left| \begin{align}   & \underline{\begin{align}   & \text{      7}\text{.5} \\  & \text{ + 12}\text{.7} \\ \end{align}} \\  & \text{    20}\text{.2} \\ \end{align} \right.\] \[\therefore \]   Distance travelled by Dinesh = 20.2 km For Ayub Distance between place A and place \[\text{D}=\text{9}.\text{3 km}\] Distance between place D and place \[\text{C}=\text{11}.\text{8 km}\] \[\therefore \] Distance between place A and place C = Distance between place A and place D + Distance between place D and place C = 9.3 km + 11.8 km = 21.1 km                                             \[\left| \begin{align}   & \underline{\begin{align}   & \text{     9}\text{.3} \\  & \text{ + 11}\text{.8} \\ \end{align}} \\  & \text{   21}\text{.1} \\ \end{align} \right.\]              \[\therefore \] Distance travelled by Ayub = 21.1 km \[\therefore \] 21.1 > 20.2 So, Ayub travelled more by 21.1 km ? 20.2 km = 0.90 km                     \[\left| \begin{align}   & \underline{\begin{align}   & \text{  21}\text{.10} \\  & \text{  20}\text{.20} \\ \end{align}} \\  & \text{    0}\text{.90} \\ \end{align} \right.\] (21.1 = 21.10; 20.2 = 20.20)


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