6th Class Mathematics Decimals

  • question_answer 19) Make five more examples and find the greater number from them.

    Answer:

    (i) Let 0.3or 0.8 \[\therefore \] \[0.3=0+\frac{3}{10}\] and \[0.8=0+\frac{8}{10}\] Here, whole parts of both numbers are same. Now, tenths part of \[0.3=\frac{3}{10}\] and tenths part of \[=0.8=\frac{8}{10}\] \[\therefore \] \[\frac{8}{10}>\frac{3}{10}\] Hence, 0.8 is greater than 0.3. (ii) Let 0.063 or 0.22 \[\therefore \] \[0.063=0+\frac{0}{10}+\frac{6}{100}+\frac{3}{1000}\] and \[0.22=0+\frac{2}{10}+\frac{2}{100}+\frac{0}{1000}\] Here, whole parts of both numbers are same. Now, tenths part of \[0.063=\frac{0}{10}\] and tenths part of \[0.22=\frac{2}{10}\] \[\therefore \] \[\frac{2}{10}>\frac{0}{10}\] Hence, 0.22 is greater than 0.063. (iii) Let 3.012 or 2.99 \[\therefore \] \[3.012=3+\frac{0}{10}+\frac{1}{100}+\frac{2}{1000}\] and \[2.99=2+\frac{9}{10}+\frac{9}{100}+\frac{0}{100}\] here, whole parts and tenths parts of both numbers are same. Now, hundredths part of \[1.34=\frac{4}{100}\] and hundredths part of \[1.39=\frac{9}{100}\] \[\therefore \] \[\frac{9}{100}>\frac{4}{100}\] Hence, 1.39 is greater than 1.34. (v) Let 1.52 and 2.05 \[\therefore \] \[1.52=1+\frac{5}{10}+\frac{2}{100}\] and \[2.05=2+\frac{0}{10}+\frac{5}{100}\] Here, whole part of 1.52 = 1 and whole part of 2.05 = 2 \[\because \] \[2>1\] Hence, 2.05 is greater than 1.52.


You need to login to perform this action.
You will be redirected in 3 sec spinner