Answer:
\[3=3+\frac{0}{10}+\frac{0}{100}\] Total distance travelled by Namita = 20 km 50 m = 20 km + 50 m \[0.8=0+\frac{8}{10}+\frac{0}{100}\]\[\therefore \] \[0.5=0+\frac{5}{10}\]and distance travelled by Namita by bus = 10 km 200 m = 10 km + 200 m \[0.05=0+0\times \frac{1}{10}+\frac{5}{100}\]\[0.5=\frac{5}{10}\] \[0.05=\frac{0}{10}\] \[\therefore \]\[\frac{5}{10}>\frac{0}{10}\] Distance travelled by auto = 20.050 km ? 10.200 km = (20.050 ? 10.200) km = 9.850 km Hence, she travels 9.850 km by auto.
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