Answer:
(a) \[{{z}^{3}}-3(z-10)={{z}^{3}}-3z+10\] \[{{(=10)}^{3}}-3(10)+10\] \[=1000-30+10\] \[=1000+10-30\] \[=1010-30=980\] (b) \[{{p}^{2}}-2p-100={{(-10)}^{2}}-2(-10)-100\] \[=100+20-100\] \[=120-100=20\]
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