Answer:
(c)
\[\underset{16g}{\mathop{C{{H}_{4}}(g)}}\,+2{{O}_{2}}(g)\to
C{{O}_{2}}(g)+\underset{36g}{\mathop{2{{H}_{2}}O(g)}}\,\]
16 g \[C{{H}_{4}}\] an complete
combustion will give 36 g of water.
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