Answer:
Element
%
Atomic mass
Relative no. of atoms
Simplest ratio
Whole no. ratio
Iron
69.9
56
\[\frac{69.9}{56}=1.248\]
\[\frac{1.248}{1.248}=1\]
\[1\times 2=2\]
Oxygen
30.1
16
\[\frac{30.1}{16}=1.88\]
\[\frac{1.88}{1.248}=1.5\]
\[1.5\times 2=3\]
Formula of compound = \[F{{e}_{2}}{{O}_{3}}\]
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