Answer:
Oxidation
state of each elements are assigned in the given reaction as
\[\overset{+1-2}{\mathop{2C{{u}_{2}}O(s)}}\,+\overset{+1-2}{\mathop{C{{u}_{2}}S(s)}}\,\to
\overset{0}{\mathop{6Cu(s)}}\,+\overset{+4-2}{\mathop{S{{O}_{2}}}}\,\]
Copper is reduced from (+1) state to zero state while sulphur
is oxidised from (-2) state to (+4) state. Thus, the given reaction is a redox
reaction.
In the given reaction, \[C{{u}^{+1}}\]
acts as oxidant because itself it is reduced while sulphur \[({{S}^{2-}})\]
acts as reductant because it is itself oxidised to (+ 4) state.
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