Answer:
Given, force applied by boy against friction=5N
Displacement on the circular path = One
cycle + Half cycled = 0 + Half cycle
= 0 + Diameter of circular path
(Displacement
depends on initial and final point)
= 0 + 2 r = 0 + 2 x 100 [r = 100 m]
= 0 + 200 = 200 m
Total
displacements = 1.5 km+200m+ 2.0km
= 1.5 x 1000 + 200+2x 1000km
(1 km= 1000m) = 3700 m
Work done by boy
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