Answer:
For first object given, u = 0 (because object dropped from
rest) and time (t) = 2s.
From second equation of motion, the distance covered by
first object in 2s is
Height of first object from the ground after 2 s = 150m -20m = 130m
For second object given, u=0 and time (t) = 2 s
From second equation of motion, the distance covered by
second object in 2 s is
Height of second object from the ground after 2s then = 100m - 20m = 80m
Now, difference in the height after 2 = 130 - 80= 50 m
The difference in heights of the objects will remain same
with time- as both the objects have been dropped from rest and are falling with
same acceleration i.e., (acceleration due to gravity).
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