question_answer 12)

A farmer moves along the boundary of a square field of side 10 m in 40 s. What will be the magnitude of displacement of the farmer at the end of 2 minutes 20 seconds?

Answer:

Figure ABCD is a square field of side 10 m. Time for one round = 40 s            Total time = 2 min 20 s   = (2 x 60 + 20) s = 140 s   Number of round completed   If farmer starts from A, it will complete 3 rounds A  at A. In the last 0.5 round starting from A, he will finish at C.