Answer:
Mass of object m1 = kg
Velocity of object before collision, u1 = 10 m s-1
Mass of wooden block, m2 = 5 kg
Velocity of wooden block before collision, u2 = 0
(i) Total momentum before the impact m1u1 + m2u2 = 1 x + 5 x 0 = 10 kg m s-1
According to the law of conservation of momentum (as no net external force acts on the system) :
Total momentum after the impact = Total momentum before the impact = 10 kg m s-1
(ii) Mass of combined object, M = mass of object + mass of block = 1 + 5 = 6 kg
Let, V = Velocity of the combined object after collision
Momentum of combined object = MV = (6V) kg m s-1
Now, momentum of combined object = Total momentum after the impact
i.e. 6 V = 10 or
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