Answer:
Here,
Distance between
object lens and eye piece= 15 cm
(a) For the
formation of image at the least distance of distinct vision,
from
the relation, we have
or
Negative
sign tells that the object for the objectlens lies to the left of the lens.
Distance
of the image from the objectlens = 15 - 5 = 10 cm
Usingweget
or
or
Magnifying
power,
(b) When the
final image is formed at infinity,then the object for the eye lens must
beplaced at its principal focus.
Therefore, and
Now using
or
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