Assume that we start with 1000
38S nuclei at time t=0. The number of 38CI is of count zero at
t= 0 and will again be zero at 
, At what value
of t, would the number of counts be a maximum?
Answer:
The
given decay sequence is
At any time t, suppose 38S has N1 (t)
active nuclei and 38CI have N2 (t) active nuclei.
= rate of formation of 38CI
and 
= net rate of
decay of 
Multiplying both sides by 
and
rearranging, 
Integrating both sides, we get
?(i)
Where C is constant of integration.
At 
Putting in (i), w get
For
maximum count; N2 =max, 
or
Or 
or 
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