Answer:
The given sequence of radioactive decay is A ® B®
C C is stable At t=0, N0 and NB =0.
As time
passes on, (increases. NA falls off exponentially to zero The number of atoms of B goes on increasing
with time, becomes maximum and finally decays to zero following
exponential decay law The variation of the number of atoms of A and B versus time
is shown in Fig. 8 (EP).4.
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