particle in the
a-decay of (a) 
Ra (b) 
Rn
. Given, 
Answer:
(a) 
Q-Value
K.E. of 
particle
(b) 
Q-value
= 220-011373
- [216.00189 + 4.00260]
= 220-011373
- 220.00449 = 0-006883 u
= 0-006883 x
931 MeV = 6.41 MeV
K.E. of 
particle
.
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