Answer:
Charge resides on the outer surface of a conductor. So the charge on inner sphere will flow towards the shell through the conducting wire. Moreover, from Gauss' law, no electric field exists inside a Gaussian surface and also the charges enclosed by a closed surface only contribute towards the field. So q2 does not matter in this case.
If q1 is positive, potential difference is also positive.
You need to login to perform this action.
You will be redirected in
3 sec