Answer:
(a) P.E.,
=
?43.47 × 10?19J
(b)
K.E. of electron in half of P.E.
(K.E.
is always positive)
Total
energy of electron
=
?27.17 + 13.585 = ?13.585 eV
Work
required to free the electron
= 0
? (?13.585) = 13.585 eV.
(c) P.E. at 1.06 ×
10?10 m separation.
=
?21.74 × 10?19J
Taking
?13.585 eV as zero of P.E., then
P.E.
of the system.
=
?27.17 ? (?13.585) = ?13.585 eV.
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