Answer:
Equation
of plane passing through the intersection of x + y + z = 1 and 2x + 3y + 4z = 5
is
(x
+ y + z ? 1) + (2x +
3y + 4z ? 5) = 0
x + (1 + ) y + (1 + ) z + (?1 ?5) = 0
..(
1)
But
it is perpendiular to plne x ? y + z = 0
(1 + 2) + (?1) (1 + 3) + 1 (1 + 4) = 0
Put
in equation
(1), we get
x ? z + 2 = 0
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