Answer:
The corner points of the feasible region determined by the
following system of linear inequalities :
2x + y 10, x + 3y x, y are (0, 0),
(5, 0), (3, 4) and (0, 5). Let Z = px + qy where p, q > 0. Conditions on P
and q so that the maximum of Z occurs at both (3, 4) and (0, 5) is
(A) p =q (B) p = 2q
(C) p = 3q (D) q = 3p
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