Answer:
Let
x and y be the number of bags of brand P and Q of cattle feed.
The
contents of each brand are given above :
Nutritional
The
above L.P.P. is given as
Minimize,
C = 250x + 200y, subject to the constraints 3x + 1.5y 2x + 3y .
L1
: 3x + 1.5 y = 18 L2 : 2.5x + 11.25 y = 45
Here
the cost is minimum at G(3, 6)
Since
the region is unbounded therefore Rs.1950 may or may not be the minimum value
of C. For this draw graph of inequality 250x + 200y < 1950.
5x
+ 4y < 39
L
: 5x + 4y = 39
Clearly
open half plane has no common point with the feasible region so minimum value
of C is Rs.1950.
For
this 3 bags of brand P and 6 bags of brand Q to be mixed to get minimum cost.
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