question_answer 1)

Minimize Z = x + 2y, subject to        

Answer:

Objective function is       L1 : 2x + y = 3                           L2 : x + 2y = 6                           Here Z is minimum at B(0, 3) and E(6, 0)       Since the region is unbounded.        may or may not be the minimum value of Z.       For this draw graph of inequality.       x + 2y < 6       L : x + 2y = 6             Clearly open half plane has no common point with the feasible region.       So minimum value of Z is 6       And optimal solution is x = 0, y = 3 or x = 6, y = 0