Answer:
Let
AB = 28 m be the length of the wire.
AC
= x m, and CB = (28 ? x) m be the two pieces of the wire.
Let
the piece AC is to be made into square of side a meters and CB into a circle of
radius r meters.
Perimeter
of the square = x
4a = x
and
circumference of the circle = 28 ? x
Combined
area of the square and the circle
A
= a2 +
Now
is
minimum when
Hence
the combined area will be minimum if length of the pieces are metres
and metres.
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