Answer:
Neutralisation
Adding Eqs. (i) and (ii)
Number of moles of ,
(Molar mass of = (4x 31) + (6
x 16) = 220
Product
formed by 1 mole of is neutralised by 8
moles
Product formed by ?-
moles of will be neutralised by
Given, Molarity of
400 mL is required.
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