question_answer 80)

      Match the complex ions given in Column I with the hybridisation and number of unpaired electrons given in Column II and assign the correct code.

Column I (Complex ion)	Column II (Hybridisation, number of unpaired electrons)
A. B.  C. D.	1. 2.   3.     4.

  Codes      A   B   C   D                        A   B   C   D (a) 3   1   4   2                  (b) 4   3   2   1 (c) 3   2   4   1                  (d) 4   1   2   3

Answer:

                    A.®(3)    B.®(1)    C.®(4)    D.®(2) Formation of inner orbital complex and outer orbital complex determines hybridisation of molecule which in turn depends upon field strength of ligand and number of vacant d orbitals. (i) Strong field ligand forms inner orbital complex with hybridisation . Weak field ligand forms outer orbital complex with hybridisation . According to VBT, hybridisation and number of unpaired electrons of coordination compounds can be calculated as MOEC (Molecular orbital electronic configuration) of  in is Hybridisation = d2sp3 n (number of unrpaired electrons) = 3 B. MOEC of is       Hybridisation =              n = 1. c. MOEC of in is. Hybridisation =                n = 2                                      D. MOEC of in  is Hybridisation =                    n = 5 Hence, correct choice can be represented by (a).