question_answer 53)

  Rate Law for the reaction A + 2B ® C is found to be          Rate = k [A] [B] Concentration of reactant 'B? is doubled, keeping the concentration of 'A' constant, the value of rate constant will be........... (a) the same                      (b) doubled (c) quadrupled                  (d) halved

Answer:

                  (b) Rate law can be written as Rate= K [A][S] Rate of reaction w.r.t B is of first order. R1 = k [A] [B] when concentration of reactant 'B' is doubled then rate (R2) Therefore; as concentration of B is doubled keeping the concentration of A constant rate of reaction doubles.