Answer:
(i)
Since the reagent (1) reduces - to - , therefore, I is either
Sn/HCl or Fe/HCl.
(ii) Since p-methylacetanilide on treatment with a mixture of cone. + cone. gives compound (2), therefore,
compound (2) must be
2-nitro-4-methylacetanilide.
(iii) Since reagent (3) brings about hydrolysis of to therefore, it must be aqueous
acid, i.e., .
(iv) Since product (4) is obtained upon treatment of 1°
aromatic amine with , therefore, compound
(4) must be a diazonium salt
2-Nitro-4= methylbenzenediazonium chloride
(v) Since reagent (5) brings about the substitution of diazo group by H or brings about
reduction of diazonium chloride, therefore, it must be aqueous hypophosphorus
acid, i.e., .
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