question_answer 62)

                  Two bodies of unequal mass are moving in the same direction with equal kinetic energy. The two bodies are brought to rest by applying retarding force of same magnitude.' How would the distance moved by them before coming to rest compare?                

Answer:

                  Work done, FS = change in K.E.                 \[\text{S=}\frac{\text{Change}\,\,\text{in}\,\,\text{K}\text{.E}\text{.}}{\text{F}}\]                 Since, change in K.E. and F in both the cases is same, therefore, both bodies will cover equal distances before coming to rest.